Please implement a function to generate the 3-digits numbers with no duplicate digits and no duplicate permutation. For example: 122 is not allowed and 123 321 is not allow, only output one of the permutations.

Question

Anonymous · Accepted Answer

def combination():
    for i in range(1,10):
        for j in range(i+1, 10):
            for k in range(j+1, 10):
                print("%d%d%d" % (i,j,k))

combination()

Nasim · Answer

Does your program generate 102?
It doesn't consider 0s.

PS · Answer

The correct answer would be:
#Python
def permute():
    for i in range(2,10):
        print(1,0,i)
###*****************
permute()

avondale · Answer

for i in range(1, 10):
  for k in range(i + 1, 10):
    print i, 0, k
  for j in range(i + 1, 10):
    for k in range(j + 1, 10):
      print i, j, k

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