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Look at the question: "What is your age?" That's different from "How old are you?" Answer accordingly. Less
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I was asked this question by the CEO of a company during my telephonic interview. Even though I didn't ask, told me his age. That just seemed weird and not very professional. This wasn't Deloitte. Less
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So many ways to find this information - in a, sort of, sneaky way. Has no-one noticed that now you not only being asked for your degrees but what year you obtained them - easy enough to extrapolate in the majority of cases... Less
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The solution is to divide in 3 groups of 3 balls each and and weight them.
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took me 20 seconds to solve. Divide the 9 into 2 groups of 4 and one aside. If the weight is the same for the 2 of 4 the one out is the heavier. If one group of 4 is heavier you know that one group has the heavier element. Divide that 4 into 2 of 2 and measure again. The heavier group of 2 has the heavier element. Measure each one now. Less
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Correction to my solution.The last step only measure ONE of the two. The weight should be 1/4 of the group of 4. So this eliminates the need to do 2 more measures. So total we will have either 1 measure only because the one left out of the first measurement was the heaviest OR 3 to find final. Less
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Split the 9 balls into 3 groups of 3. Weight two random groups against each other. If it tilts then take 2 random balls from the heavier group to weight, one on each side. If it balances, the heavy ball is the one you didn't weight. If it tilts you know which one is the heaviest. In the first weigh-in, if it balances you know that the heavy ball is in the third group of 3 you didn't weigh. So you take 2 random balls from that group and weigh them one on each side.If it balances, the heavy ball is the one you didn't weight. If it tilts you know which one is the heaviest. Less
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Like a google question. Put all nine on the scale. You weigh 4:5. Then remove one. Whichever way the balance tilts has the heavier ball(unless you luckily pick the heavier ball and they balance out and you get it on the first shot). Remove the 4 balls that weigh less. Now you only have 4 balls. One of which you know is the heavier ball. Place two balls on either side of the scale again. Tada! Less
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I drew it out on paper to figure out the answer. This was actually the only fun part of the interview. Less
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In the first round,people were selected based on their marks. If a person scored more in Big data topic then he was grouped to the Bid data team and personal interview questions were asked only in big data. Screened students were grouped into four teams for the personal interview. Personal Interview was rather easy but it depends the HR's mind to select you. Less
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TCS is coming to our college for campus selection. It now has a new platform called TCS' Digital Enterprise in which it selects 200 people out of the whole country. What is actually asked in this interview process? Less
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how many people get offers?? also pls any sample ques...
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False
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A bit frustrating since they don't know you and will make an assessment based on how you score. I don't think a test can say anything about you except that you are either good or bad at testing. The real world works differently. But I guess it is where we're heading. If you haven't seen Gattaca, the movie, you should - I'm sure in the very near future your ability to do a job will be based on your DNA profile. Less
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True
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shouldn't it be ['d', 'e', 'f', 'g', 'a', 'b', 'c']
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package uber; public class RotateArray { public static void main(String[] args) { // ['a', 'b', 'c', 'd', 'e', 'f', 'g'] z=3 => ['e', 'f', 'g', 'a', 'b', 'c', 'd'] char[] array = {'a', 'b', 'c', 'd', 'e', 'f', 'g'}; int index=3; char[] temp = new char[index+1]; for(int i=0;i Less
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public class RotateArray { public static void main(String[] args) { // ['a', 'b', 'c', 'd', 'e', 'f', 'g'] z=3 => ['e', 'f', 'g', 'a', 'b', 'c', 'd'] char[] array = {'a', 'b', 'c', 'd', 'e', 'f', 'g'}; int index=3; char[] temp = new char[index+1]; for(int i=0;i Less
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Cliche response...
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Good Response!
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My never give up attitude often makes for stress filled days
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traceroute issues packet(s) for the destination with RTT set as 1 on random ports which, on reaching the first router, expires and ICMP expired message is received back. Now RTT is set to 2 and more packets are sent. They expire on the second router and ICMP messages are returned back. This is done to map the reachability of source to the destination. This methodology is gradually extended until we reach the destination (and ICMP messages starts coming back from them). Less
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TTL timer set for dummy packets increases everytime....