Design engineer Interview Questions
A design engineer evaluates and improves different aspects of a product, such as safety and functionality. When interviewing for this job, expect to answer scenario-based and technical questions. Get ready to speak about your experience with product design, communication and attention to detail.
Top Design Engineer Interview Questions & How To Answer
Here are three top design engineer interview questions and tips on how to answer them:
Question No. 1: What types of software and devices have you used during your career as a design engineer?
How to answer: A design engineer should be skilled in industry-specific software and devices. Demonstrate to the hiring manager that you have technology expertise by specifying the computer-aided design (CAD) and computer-aided engineering (CAE) software you use. Additionally, describe any technologies specific to your design engineering career, for example, the MOSFET circuit design for a circuit design engineer position.
Question No. 2: How do you manage your time when working on several design engineering projects?
How to answer: Address this personality-based question by identifying the techniques you would use to organise your time in this scenario. For example, you can discuss creating timelines, scheduling and prioritising tasks, and meeting deadlines.
Question No. 3: While working on a design engineering project, you experience a setback. How do you stay on track?
How to answer: With this question, the hiring manager is evaluating your motivational abilities. Talk about a strategy you use to stay motivated. Try to give an experience-based answer, such as the self-motivation technique you used when you misunderstood a design request parameter provided by the research and development team.
need to join tomorrow are you ready?
13 Answers
Given a string find the first non-repeated character.
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@Rajiv : Your solution is completely wrong. It will fail for input of "aaa" Reason: on first check, you insert "a". On next check you remove it. On next check you again insert it and return that as your answer, even though it was repeated thrice. Less
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program to find first non repeating character in a string c# - three ways
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My python implementation: def firstNonRepeatingCharacter(inputString): hashmap = {} for x in inputString: if (x in hashmap): hashmap[x] = hashmap[x] + 1 else: hashmap[x] = 1 for x in inputString: if (hashmap[x] > 1): continue else: return x return "No nonrepeating character found" Less
Basic MOSFET, CMOS questions were asked.
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Hey, you should feel glad that you weren't accepted by them. This company is very cheap and doesn't treat its employees well. Less
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I guess...but it is not the right way to interview candidates don't you think?
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That's really sad. They should rather go with Skype or any other means to interview. Now,. I have got an on-site call for Digital circuit design and I am giving it a serious thought 🤔 Less
There is a refrigerator in a perfectly insulated room. The door is then opened. Is it an open or closed system? After a long time has passed, has the temperature in the room increased or decreased?
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It is a closed system as electricity is adding energy into the room. After a long time passes, the temperature increases as there's energy going in, but not leaving. Less
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It's a closed system. Since the efficiency of heat transfer is not 100%, will generate heat and eventually heat up the room. Less
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Since there is energy going into the room, it is open system without mass transfer. The room temperature will increase. Less
Create a 8 input AND gate using 3 4:1 muxes
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Without an enable bit on at least one of the mux's the maximum inputs would be 7. Less
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I don't see it being possible with three standard 4-1 muxes... Using 4, this question is straight forward... The two selects of each mux are your 8 inputs... tie out put of each mux to the (11) case input to the mux. Less
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We need 3 4:1 MUX and a And gate. Are we allowed to use 'and' gate?
Show me the back of an iPhone and asked me how it might have been manufactured.
8 Answers
design a full adder with 2-1 mux
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full adder can be got by 2 half adders and one OR gate; one half adder can be got by XOR, AND. Therefore, we need only OR, AND, XOR. All these three gates can be got by using MUX.? Less
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Can be implemented using 8 Muxes.
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sum = a xor b xor cin carry = (a xor b) cin + ab You can easiy make XOR, OR AND, NOT using 2:1 mux. So 8 mux ?!? Less
If I have a solid rod and hollow rod with the same mass and I let them slide in a ramp. Which one reaches the bottom first and why?
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Since they've clearly told sliding. Acceleration along the ramp is independent of the mass or the moment of Inertia. Hence, both reaches down at the same time. Less
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Solid bar, smaller moment of inertia allows it to spin faster
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Solid reaches first
CMOS Inverter , how to reduce the drive strength of Minimum size inverter
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"more the Ids, the lesser the drive strength is" This is exactly opposite of the actual fact...! Less
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Use body effect, reverse biasing, this will reduce the drain current. another way can be change the gate input, according to the I-V characteristic Less
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the first answer is definitely wrong, to decrease the driving capacity, please size down the ratio! Less
design a combinational circuit which counts the number of 1s in a 7-bit input .
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@Akash, Adder C should be the 7th bit and the sum of adder a and b right? not carry Less
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It can be done by two ways Clocked Circuit: Use a one bit adder and a register. Output of the register acts as 2nd input to the adder. Half adder can also be used. Combinational Circuit: We can do it in 4 full adders. For the adders A and B, let 6 bits be the inputs. For adders C, use the 7th bit and Carry of adder A and B. Adder C gives sum as bit 0. For adder D, use carry from all three adders. The sum is bit 1 and carry is bit 2. Less
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depending on resource and timing constraints, you can use a cascade of adders, where you repeatdly add each bit starting with bit 7 to each other. this is slow because the critical path is on the Cin -> Cout. to improve, you can go further and use a 7bit decoder/any arrangement of decoder/column muxer + decoder for a lookup, which is essentially an SRAM array design to store this value so that next time you try to do this computation, you can directly access it. Essentially caching computation result. This requires extra circuitry overhead, but means you only have to compute the sums once. Less