associate interview questions shared by candidates
What angle is between an hour and a minute arrows when time is 5:30?13 Answers
I think you got that wrong bud, the answer should be 15 degrees.
Yeah, you right man. 15 is correct.
WHY 15? I think it should be 30..
15 degrees because at 5:30 the hour arrow is not at 5 but in the middle between the 5 and 6
15 degrees plus or minus 180 degrees. (who knows how accurate the clock is)
45/3=15 15 is the correct answer
it is 30 degree WHY 15 ?
minTheta = 30*(360/60) = 180 hourTheta = 5*(360/12) + (360/12) * (30/60) = 165 so the difference is 15 degree
Assume a circle is 360° and you 60 grades reprsenting each one 1 minute. 360/6=6°, so 1 degree equals 1 minute At 5.30pm the arrow will be pointing at the third grade between 5 and 6 which means there are 2 left: 2*6=12° is the accurate answer ;)
No, at 5:30 the arrow will be pointing in the middle between the second and third grade = therefore its 2.5*6 = 15... or 30/2 = 15 !
the correct answer is 15 degree right?
I don't get your complicated formula... a full circle is 360 degree so a quarter of it, equal to 90 degrees. From 3-6 separated to three equal correspondent angles by 4 and 5 so 90/3 = 30 degree (clockwise) then 360 - 30 =330 degree (anticlockwise)
toss 100 coins, what is the probability of getting more than 60 heads?7 Answers
use normal dist to estimate binary dist, but notice the tail
binomial distribution (100 60) (1/2)^60 (1/2)^40
100 C 60 (0.5)^100 will get one prob of 60 heads, not 60 and above. Interview candidate is correct. You will most likely have to use normal dist. to estimate the binom dist given time constraints. A google search can inform one how to do this
simply use CLT
don't have latex installed, so sorry in advance. answer is: sum[i=60 to i=100] of (100 choose i)/(2^100)
As pointed out, use a normal approximation for the sum. Define an RV called X. X = 0 for tails. X = 1 for heads. We have: E[X] = 1/2, Var[X] = 1/4. Now denote S = sum(X), where the sum runs over 100 realizations. So: E[S] = 50, Var[S] = 25. (The event are uncorrelated, so their covariance is zero, hence we can just sum variances here.) Then P(S >= 60) corresponds to P ( (S - 50)/sqrt(25) >= (60 - 50) / sqrt(25)). Note that we just subtracted the mean and divided by the standard deviation. This renders the term at the LHS a standard normal variable. So we need: P(N >= 2), where N is standard normal. If no computer is allowed, one can remember that the 97.5% percentile lies at 1.96. (If you often compute two-sided 95% confidence intervals, then you might know this number.) Or remember that within 2 sigma of the mean, 95 percent of the realizations lie. Since the distribution is symmetric, you will come to the same conclusion. So we estimate: P(S > 60) = 2.5%. In summary: make two approximations: one for going from Binomial to Normal, and a second for estimating the probability.
Using the normal approximation to a binomial distribution... Find the z value (i.e. z=x-u/st) u=mean u=np=100x0.5=50 st=standard deviation st=sq(npq)=sq(100x0.5x0.5)=5 x= 60-0.5=59.5 (i.e. continuity correction) z=59.5-50/5=1.9 Therefore P(x≥ 60)=P(z≥ 1.9)= 1-P(z≤1.9)= 1- 0.9713=0.0287 Answer: 2.87 % chance of getting more than 60 heads
They asked when I took a decision which seemed wrong at the beginning but after a certain amount of time it revealed itself to be the right one.3 Answers
I had no idea what to answer tbh. This is were I Failed
Do They told you that was the reason why they didn't take you?
I would have answered: Back in school we did a science experiment where we mixed 50 ml of water and 50 ml of alcohol together, we did this in a group and my group had spilled a little. When the time came to measure how much liquid we had in the vile ors came up at about 96 ml and my own conclusion was that the alcohol had mixed with the water, and this mixture was more dense than the two liquids separately, but my group disagreed since we had spilled some. But I stuck with my answer because, why would the teacher make us mix these two together if it did not have a special property? well, turns out.. I was right, alcohol and water mixed together do become more dense and cause there to be less liquid in the vile.
"You have 25 horses, no stop watch, and you can only race 5 horses at a time. What is the minimum number of races you need in order to find the fastest horse? How would you find the second fastest horse?"3 Answers
Hold 5 races, each of 5 new horses, then have a final 6th race which races all the winners of the previous 5 races. Answer: 6 races To find the second fastest, the process is the same as before except race the 2nd fastest horses from each race, the fastest horse of all the 2nd place horses is the overall second fastest.
Surely there is more to determining the second fastest horse overall... Having found the fastest horse using the method described above, after the 6th race, one would be left the fastest horse, the 4 losing horses from the 6th race and 20 other horses defeated in the first round of races. The second fastest horse is not the horse that came second in the 6th race, because there is a chance that the second fastest horse overall could have been in the same race as the eventual overall winner in the first round of races (thereby not progressing to the 6th race despite being faster than the 4 of the horses in the 6th race). Answer: So to be sure of identifying the second fastest horse overall you would have an 7th race of all the second placed horses from the first 5 races. Then, you would hold an 8th race in which the winner of the 7th race competes against the 4 losing horses from the 6th race. The winner of this race would be the second fastest overall.
Have 6 races as above for the fastest horse. Say the fastest horse overall initially won the 3rd race, then to find the 2nd fastest horse, you race the 2nd place horse from the 3rd race with the four losing horses (i.e. the four winning horses in races 1, 2, 4 & 5) from the 6th race. The winner of this 7th race is the 2nd fastest horse
What would you do if your client drops 50% in sales? (Due to recession in the economy)3 Answers
Tell me about a time you had a difficult client? What went wrong? How did you deal with it?
If its due to recession that is external causes. However there are a couple of approaches to take: 1. Analyse the industry to see if the other companies have sales revenue decrease 2. Advice the client to switch market segment or decrease prices.
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why do you want to work for us2 Answers
I wanna work with you so that i can pave my future and again i love working with people and socializing with different people and earn some knowledge in customer service
I wanna work with you in order to advance my career/experience .....
What would you do if one team member frequently underperforms?3 Answers
I'd definitely offer my help in the following form: - I'd ask, if he'd be interested in sitting down together and talking his situation through - I'd try to find out, why the member thinks he/she is underperforming and what the problems are in not meeting the expectations - if the problems are more of a psychological nature I'd offer my help in finding professional support - I'd suggest to help by -> practicing his tasks with me and suggesting improvements -> encouraging him/her to talk with other peers and the team lead about his situation, thus maybe lowering his/her goals for a certain period of time, to lower the pressure -> sharing my "secrets to success", my actions to reach my goals
I think this first of all depends on whether I have responsibility over his/her performance (e.g. as project leader) or not (so we are just colleagues). Let's assume I'm a colleague. Probably approaching the other person is the most difficult task, since he/she is likely somewhat ashamed about the underperformance and struggles to discuss it. So I would try to shift such a talk in a very causal ambience, e.g. going for a beer or so. Before mentioning the performance topic, I would start by trying to understand whether the person is having a good time in the company/private life/... (if they eventually mention their underperformance first, things are much easier). Once the performance topic is reached, my further behavior would depend on her reaction > in case the person seems a little under-confident and fussed about the work, I would offer i) some immediate help by discussing the work process and clarifying some issues, ii) some coaching (in case I am good in the task) or iii) to switch roles for some time (in case I do something different) and see whether they get better along with what I do. > in case the person does not seem to care a lot about work performance, I would most likely report the case the team leader.
Estimate market size and strategy to enter the new market2 Answers
Question was related to Linkedin as a whole or for specific solution or product? what was the other case? You mentioned there were 2 case interviews.
yes i would like to know more about the case studies,
How would you launch YouTube in Turkey?2 Answers
YouTube is banned in Turkey because they allow users to post videos that criticize Ataturk.
YouTube is not banned anymore, plus the majority of the people could still access it even with the ban.
Where do you see yourself in 5 years, what are your experience with customer support, why did you apply for the job, what are your skill sets.1 Answer
Convergys wants people that can be taught how to use the systems available and who can effectively communicate to customers.