Interview Question
Data Scientist Interview

MetaGiven an list A of objects and another list B which is identical to A except that one element is removed, find that removed element.
Interview Answers
19 Answers
All these supposed answers are missing the point, and this question isn't even worded correctly. It should be lists of NUMBERS, not "objects". Anyway, the question is asking how you figure out the number that is missing from list B, which is identical to list A except one number is missing. Before getting into the coding, think about it logically  how would you find this? The answer of course is to sum all the numbers in A, sum all the numbers in B, subtract the sum of B from the sum of A, and that gives you the number.
Anonymous on
select b.element from b left join a on b.element = a.element where a.element is null
Anonymous on
In Python: (just numbers) def rem_elem_num(listA,listB): sumA = 0 sumB = 0 for i in listA: sumA += i for j in listB: sumB += j return sumAsumB (general) def rem_elem(listA, listB): dictB = {} for j in listB: dictB[j] = None for i in listA: if i not in dictB: return i
BurmesePython on
How about this in python, will this work? x = set(listA)set(listB) print(x)
Anonymous on
missing_letters = [] for letter in A: if letter in B: pass else: missing_letters.append(letter) print (missing_letters)
Teni on
In R: removed_element < A[which(!A %in% B)] removed_element
Anonymous on
Select * from A except Select * from B
Anonymous on
I think it is a coding in algorithm rather than SQL query. So here is my take: def ret_miss(A, B): k = len(A) if k == 2: if A[1] == B[0]: return A[0] elif A[0] == B[0]: return A[1] n = k/2 print A[n], B[n] if A[n] == B[n]: A= A[n:] B=B[n:] else: A=A[:n+1] B=B[:n+1] print A,B return ret_miss(A,B) This works nicely actually.
Chaiwala on
# python code def missing_obj(original_lst, new_lst): for x in new_lst: original_lst.remove(x) return original_lst
JPC on
In SQL: SELECT A.object FROM A LEFT JOIN B ON A.object = B.object WHERE B.object IS NULL;
Morgan on
Careful, there could be a repeated object that's being removed. i.e. A = [3, 4, 5, 6, 5] B = [3, 4, 6, 5] This is how I would do it on Python (works for numbers and strings) def missingval(lA, lB): a = sorted(lA) b = sorted(lB) c = None for i in range(len(b)): if a[i] != b[i]: c = a[i] break if c is None: c = a[1] print(c, "was removed from list A")
Anonymous on
SQL: select a.list as a, b.list as b from ListA as a full join ListB as b on a.list = b.list where a.list eq '' OR b.list eq "" ;
Anonymous on
XOR all elements
Anonymous on
A = [1,2,3,4,5,6,7,8] B = [1,2,3,4,5,6,8] [i for i in A if i not in B]
Anonymous on
find the sum of the two list and subtract. ans = sum(a)  sum(b) where a and b are list of numbers.
Anonymous on
Depends on the kind of elements in the lists. If they're numbers, sum(A) minus sum(B) will give the missing element. If they're characters/strings, just dump the elements of A into a dictionary and check each element in B for existence in A.
dopey on
[i for i in A if i not in [j for j in B]]
Beena on
Python: sum(A)sum(B)
Anonymous on
two ways to do it using sql: 1. select * from A where not in (select * from B)  assuming you know what element you're looking for 2. select * from (select * from A UNION select * from B) having count(element) = 1  again assuming you know the element
Anonymous on